John Davidson

Message:

I have this PHP variable:

$values = $response->getValues();

That print this array:

Array ( [0] => Array ( [0] => 16777439-3 ) [1] => Array ( [0] => 17425847-3 ) )

Then I have this code to find a value inside of that array:

if (in_array("16777439-3", $values)) {



    echo "Is in array";



}else{



    echo "Isn't in array";



}

But all the time it returns "Isn't in array"

Also I've tried to convert my original variable with:

$array2 = json_decode(json_encode($values), true);

But also I'm getting the same return.

---

My Answer:
The `in_array()` function in PHP is used to check if a value exists in an array. It takes two parameters: the value to search for and the array to search in.

Here's an example of how to use the `in_array()` function:

php
$fruits = array("apple", "banana", "orange", "grape");

if (in_array("banana", $fruits)) {
echo "Found banana in the array";
} else {
echo "Banana not found in the array";
}


In this example, the `in_array()` function is used to check if the value "banana" exists in the `$fruits` array. If it does, it will output "Found banana in the array", otherwise it will output "Banana not found in the array".