John Davidson

Message:

i want running bash script with passing 2 parameter and show with bash script create file.txt

$email = "omdik";

$password = "123";



$page = shell_exec("/var/www/html/aktiva-development/test.sh $email, $password");

and this file test.sh

#!/bin/bash

echo "username : $1 dan password : $2" > /tmp/cekhasil.txt

why the file not create, like the bash command is not running, but if script bash like ls dir the dir list will be show, and the access permision for file and folder i was change to 777

thank you for help.

---

My Answer:
$email = "example@example.com";
$param1 = "parameter1";
$param2 = "parameter2";

$output = shell_exec("bash script.sh $param1 $param2 $email");

echo $output;