John Davidson

Message:

I have a php file results.php with a grid of different items (each item is a row from the result of a certain query). When I click an item it takes me to another php file details.php where I want to show more details in the new page about the specific item I clicked.

function showAsItem($row) {

    $defaultValue = $row[1];

    $itemClassname="item";

    $titleClassname="title";

    $imageClassname="image";

    $infoClassname="infolist";

    $link="details.php";

    $target="_top";

    $img="https://barcelonando.com/es/wp-content/uploads/2012/12/barceloneta.jpg";

    $alt="Imagen de $row";

    

    echo '<div class="'.$itemClassname.'">';

        echo '<div class="'  .$titleClassname.  '">';

            echo '<a href="'.$link.'" target="' .$target. '">' .ucfirst($row[0]). '</a>';

        echo '</div>';

        echo '<div class="'  .$imageClassname.  '">';

            echo '<a href="' .$link. '" target="' .$target. '">';

            echo '<img src="'  .$img. '" alt="'  .$alt.  '"/>';

            echo '</a>';

        echo '</div>';

        echo '<div class="'  .$infoClassname.  '">';

            echo '<ul>';

            echo '<li> Poblaci&oacute;n: '  .$row[1]. '</li>';

            echo '<li> Esperanza de vida: '  .$defaultValue. '</li>';

            echo '<li> Inmigrantes: '  .$defaultValue. '</li>';

            echo '<li> Transportes: '  .$defaultValue. '</li>';

            echo '<li> Accidentes: '  .$defaultValue. '</li>';

            echo '</ul>';

        echo '</div>';

    echo '</div>';

}

I only know how to send info from one webpage to another when it is an input type, but in this case I want to send the item static info (I just need to send the name of the item I clicked). Any idea about how to do it?

---

My Answer:
"item";
echo "";
}

// In results.php
$query = "SELECT * FROM items";
$result = mysqli_query($conn, $query);

while ($row = mysqli_fetch_array($result)) {
showAsItem($row);
}

// In details.php
$id = $_GET['id'];
$query = "SELECT * FROM items WHERE id = $id";
$result = mysqli_query($conn, $query);
$row = mysqli_fetch_array($result);

echo "Details for item $id:";
echo "

";

print_r($row);

echo "

";