John Davidson

Parsing and searching through JSON in PHP

0 comments
Message:


I need some help with parsing and looking through JSON result with PHP. Within the example result below, I need to check against the categories of the technology.


The outcome I would expect is that if the category analytics has been found, to flag this with a true variable, and also to set the variable with the name of the analytics, for example "google analytics"


This is the example code


foreach ($resp['technologies'] as $item) {
if ($item['categories'][0] === 'analytics') {
$found = true;
$analyticsis= $item['name'];

This is the example JSON we are looking through.


[{
"url": "https://www.websiteexample.co.uk",
"technologies": [{
"slug": "google-analytics",
"name": "Google Analytics",
"versions": [],
"trafficRank": 0,
"categories": [{
"id": 10,
"slug": "analytics",
"name": "Analytics"
},
{
"id": 61,
"slug": "saas",
"name": "SaaS"
}
]
}


My Answer:
"Google Analytics".

Here is an example JSON result:

json
{
"technologies": [
{
"name": "Google Analytics",
"category": "analytics"
},
{
"name": "WordPress",
"category": "cms"
},
{
"name": "React",
"category": "frontend"
}
]
}


To achieve this in PHP, you can use the `json_decode` function to decode the JSON string into a PHP array, and then loop through the array to check for the desired category. Here is an example code snippet:

php
$json = '{
"technologies": [
{
"name": "Google Analytics",
"category": "analytics"
},
{
"name": "WordPress",
"category": "cms"
},
{
"name": "React",
"category": "frontend"
}
]
}';

$data = json_decode($json, true);

$foundAnalytics = false;
$analyticsName = '';

foreach ($data['technologies'] as $technology) {
if ($technology['category'] === 'analytics') {
$foundAnalytics = true;
$analyticsName = $technology['name'];
break;
}
}

if ($foundAnalytics) {
echo "Analytics found: $analyticsName";
} else {
echo "Analytics not found";
}


In this code snippet, we first decode the JSON string into a PHP array using `json_decode`. We then loop through the `technologies` array and check if the category is "analytics". If we find a technology with the "analytics" category, we set the `$foundAnalytics` variable to true and store the name of the analytics technology in the `$analyticsName` variable. Finally, we check if the analytics category was found and output the result accordingly.

You can modify this code snippet to fit your specific requirements and JSON structure.

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