John Davidson

Message:

I have a small part of the code. I have to get the data using ajax but I am getting only one field.

There is no issue with the value and I am getting the correct one. I have to send the result to ajax but I am getting only one field.

I believe there is some issue with my array.

$result=[];



      if ($haschange['fb']==1) {

       $result[]="<input type='text' value='".$social_links['fb']."'>";

      }

      if ($haschange['twitter']==1) {

        $result[]="<input type='text' value='".$social_links['twitter']."'>";

      }

       if ($haschange['linkedin']==1) {

         $result[]="<input type='text' value='".$social_links['linkedin']."'>";

      }

       if ($haschange['instagram']==1) {

         $result[]="<input type='text' value='".$social_links['instagram']."'>";

       

      }

    



echo json_encode($result);

exit();

script

<script type="text/javascript">

  $(document).on('click', '.pendingContent', function(){  

  

      var id=$(this).data("id");

     //alert(id);

      $.ajax({

              url: 'process.php',

              method:'post',

              dataType: "json", 

              data:{action:"pendingContent",id:id},  

              success: function(data){

                $('#shaedcontent').html(data);

                $("#pendingContent").modal('show');

              }

            });

      });

</script>

---

My Answer:
array("fb" => $haschange['fb']);