John Davidson

Message:

I am trying to put the value of timestamp in the datetime-local value of the input.

This is how I am trying to do it:

<?php $new_datetime = date("c", strtotime($account['foo'])); ?>

<input class="numberinput" type="datetime-local" placeholder="Enter foo" value="<?php echo 

`$new_datetime ?>" name="foo" id="foo" required>`

In $new_datetime is this value: 2021-03-17T16:38:00+01:00

this is what i tried:

$begindate = date("d-m-Y", strtotime($account['foo']));

$begintime = date("H:i", strtotime($account['foo']));

$begintijd = $begindate." ".$begintime;

echo $begintijd; // 17-03-2021 16:38 <--- prints this

why does it not put it in value???

---

My Answer:
It looks like you are using the wrong format for the datetime-local input type. The value for datetime-local input type should be in the format "YYYY-MM-DDTHH:MM", without the timezone offset.

You can try formatting the timestamp in the correct format before setting it as the value for the input field. Here's an example:

php
$new_datetime = date("Y-m-d\TH:i", strtotime($account['foo']));


Then, you can set this formatted datetime as the value for the input field:

php



This should display the timestamp from your SQL database in the correct format for the datetime-local input type.