John Davidson

Message:

I am trying to echo the variable $ipss instead of the string below where you see "HERE" in my URL but I don't know how to do it.

<?php $url = "http://api.openweathermap.org/data/2.5/weather?q=HERE&lang=fr&units=metric&appid=b5f11a80423d0d4dae64f1ec1a653edf"; ?>

I have tried this to output the value of the variable in place but it doesn't work:

<?php $url = "http://api.openweathermap.org/data/2.5/weather?q=echo $ipss&lang=fr&units=metric&appid=b5f11a80423d0d4dae64f1ec1a653edf"; ?>

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My Answer:
To include a variable within a URL in PHP, you can concatenate the variable with the rest of the URL string. Here's an example:

php
$ipss = "example.com";
echo "https://www." . $ipss . "/page";
?>


In this example, the variable `$ipss` is concatenated with the rest of the URL string to form the complete URL. When you echo this statement, it will output `https://www.example.com/page`.