John Davidson

Message:

Suppose I've got a library class and an autoloader that includes any class that starts with MyLibrary_ from the classes directory:

spl_autoload_register(

    function ($classname) {



        if(class_exists($classname)) return;



        if(strpos($classname, 'MyLibrary_') !== 0) return;



        //if such class exists, include it

        $class_file = __DIR__.'/classes/'.$classname.'.php';

        if(file_exists($class_file)){

            include $class_file;

        }

    }

);

if(!class_exists('Someprefix_MyLibrary')){

    class Someprefix_MyLibrary{}

}

$mylibrary = new Someprefix_MyLibrary;

Then, in the /classes/strings.php file there is a child class MyLibrary_strings:

class MyLibrary_strings extends Someprefix_MyLibrary{



   public punction __construct(){

       $this->strings = new self(); //not declared in parent class

   }



   //make first letter capital in a multi-byte string

    public function mb_ucfirst($string, $encoding){

        $firstChar = mb_substr($string, 0, 1, $encoding);

        $then = mb_substr($string, 1, null, $encoding);

        return mb_strtoupper($firstChar, $encoding) . $then;

    }

}

I would like to do something like:

$new_string = $mylibrary->strings->mb_ucfirst('somestring');

Unless I declare public $strings in parent class, my IDE warns me that a property has been declared dynamically, and in other child classes, the strings property will be marked as not found. What I want is to automatically include a parent property for each file that has been placed into the classes directory OR for every child class of Someprefix_MyLibrary, without having to manually declare every property.

Is it possible to do it, and how?

---

My Answer:
determine if a variable is an array in PHP using the `is_array()` function. This function returns `true` if the variable is an array and `false` if it is not. Here is an example:

php
$variable = [1, 2, 3];

if (is_array($variable)) {
echo "The variable is an array";
} else {
echo "The variable is not an array";
}


This code will output "The variable is an array" since the variable `$variable` is an array.