John Davidson

Message:

I know this works:

<?php 



class MyDTO 

{

    public $foo;

    public $bar;

}



$dto = new MyDTO();

$dto->foo = 42;

$dto->bar = false;



echo json_encode($dto); // {"foo": 42, "bar": false}

But I cannot find any references to such json_encode() behavior in the PHP docs. So my question: is it ok to rely on it?

Alternatively, I can implement \JsonSerializable interface, but I don't like to repeat DTO fields inside \JsonSerializable#jsonSerialize() considering those DTOs will contain only public fields.

---

My Answer:
php
class Person {
public $name = "John";
public $age = 30;
}

$person = new Person();
echo json_encode($person);


This will output:

json
{"name":"John","age":30}