John Davidson

Message:

How can I download the versions from the link? I tried to do it with regEx but it didn't work as I wanted.

I wish it would work like this (Where I gave NULL, there is nothing to choose from)

https://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js > 1.11.2

https://ajax.googleapis.com/ajax/libs/jquery/v1.11.2/jquery.min.js > 1.11.2

https://ajax.googleapis.com/ajax/libs/jquery/version-1.11.2/jquery.min.js > 1.11.2

https://ajax.googleapis.com/ajax/libs/jquery/1-11-2/jquery.min.js > NULL

https://ajax.googleapis.com/ajax/libs/jquery/1112/jquery.min.js > NULL

https://www.google.com/recaptcha/api.js?render=6LdBsjgVaoTJ8rC-Npzz16bnAE > NULL

My regEx: /([0-9]+\.?)+/

Thank you in advance for your help :)

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My Answer:
You can use regular expressions in PHP to extract the version number from the URL. Here's an example code snippet that demonstrates how you can achieve this:

php
$url = 'https://ajax.googleapis.com/ajax/libs/jquery/1.11.2/jquery.min.js';

// Define the regex pattern to match the version number
$pattern = '/\/(\d+\.\d+\.\d+)\//';

// Perform the regex match
preg_match($pattern, $url, $matches);

// Extract the version number from the matched result
$version = isset($matches[1]) ? $matches[1] : NULL;

// Output the version number
echo $version;


In this code snippet, we define a regex pattern that matches a version number in the format of "x.x.x" within the URL. We then use `preg_match()` function to perform the regex match on the URL and extract the version number from the matched result. Finally, we output the extracted version number.

You can adjust the regex pattern as needed to match different version number formats in the URL.