John Davidson

Message:

Given an array of integers nums and an integer target, return indices of the two numbers such that they add up to target. I've tried a few modified versions of the solution below.

function twoSum($nums, $target) {

    $arr = array();

    for($i = 0; $i < count($nums); $i++){

        

        if($nums[$i] + $nums[$i+1] == $target){

            array_push($arr, array_search($nums[$i], $nums), array_search($nums[++$i], $nums));

            break;

        }

    }

    return $arr;

}

When passed three test cases the first two return the correct outcome the last case returns the first correct index but the last index is (technically) incorrect.

Test cases used:

1. nums = [2,7,11,15], target = 9
   
   expected output: [0,1]
   
   actual output: [0,1]

   
   



2. nums = [3,2,4], target = 6
   
   expected output: [1,2]
   
   actual output: [1,2]

   
   



3. nums = [3,3], target = 6
   
   expected output: [0,1]
   
   actual output: [0,0]

   
   

---

My Answer:
The issue in the third test case is that the for loop is not correctly incrementing the index. The problem lies in the line `$nums[++$i]`, where the increment operator `++` is used incorrectly.

To fix this issue, you can modify the code as follows:

php
function twoSum($nums, $target) {
$arr = array();
for($i = 0; $i < count($nums); $i++){
for($j = $i + 1; $j < count($nums); $j++){
if($nums[$i] + $nums[$j] == $target){
array_push($arr, $i, $j);
return $arr;
}
}
}
return $arr;
}


This modified code uses nested loops to iterate through all possible pairs of numbers in the array. It correctly increments the index and checks for the target sum. This should now return the correct output for all test cases.