John Davidson

Message:

So, I,been trying to write a code for a "Dice generator" and I want it to generate random numbers (from 1-6) a x numbers of times.
The x number of times is given as a parameter by the user through the terminal, with this "$argc argv" function, but this is not really important.

What I want to know is: how do I generate random values x number of times?

FOR EXAMPLE:

User input: 4

Output: 5 3 6 8

User input: 3

Output: 5 1 2

This is what I am trying to write. I used the array_rand function with the array as a parameter, and the number of times I want as the second parameter, but It does not work! What am I not getting here?

<?php



if ($argc < 2) {

    print "You have to write at least one parameter" .PHP_EOL;

    exit(1);

}

//This is the variable that corresponds to the number of times the user will give on the Terminal as a parameter.

//$randoms = $argv[1];

$num = 3;

$diceNumbers = [1, 2, 3, 4, 5, 6];

$keys = array_rand($diceNumbers, $num);



print $diceNumbers[$keys[0]]." ".$diceNumbers[$keys[1]] .PHP_EOL;



?>

---

My Answer:
You are on the right track with using the array_rand function, but you need to loop through the keys array to get all the random elements. Here is an updated version of your code that should work:

php

if ($argc < 2) {
print "You have to write at least one parameter" . PHP_EOL;
exit(1);
}

$num = $argv[1];
$diceNumbers = [1, 2, 3, 4, 5, 6];
$keys = array_rand($diceNumbers, $num);

foreach ($keys as $key) {
print $diceNumbers[$key] . " ";
}

print PHP_EOL;

?>


With this code, you should be able to generate the specified number of random elements from the diceNumbers array. Just make sure to pass the desired number as a command line argument when running the script.