Message:

I have 3 .txt files (name.txt, cardnumber.txt, expirydate.txt) and 1 html form with one input (name).

I want to read the user input, check if the input matches any line in name.txt, and then display string in all .txt files with the same line where the input found + an image.

EXAMPLE

name.txt:

John Doe

Jane Doe

cardnumber.txt:

1111 2222 3333 4444

4444 3333 2222 1111

expirydate.txt:

2025-12-31

1999-09-25

user input:
Jane Doe

desired output:

Jane Doe 4444 3333 2222 1111 1999-09-25

Here's my code:

<html>

<body>

<form method="POST" class="form">

        <h2>name: </h2><br>

        <input type="text" class="name" name="name" id="name"><br>

        <input type="submit" name="submit" id="submit" value="search">

    </form>



    <?php

    //convert files to arrays

    $file1 = 'name.txt';

    $file2 = 'cardnumber.txt';

    $file3 = 'expirydate.txt';

    $namefile       = file($file1);

    $cardnumberfile = file($file2);

    $expirydatefile = file($file3);



    //put user input to variable

    $search      = $_POST["name"];



    //display element with the same index in array namefile, cardnumberfile, and expirydatefile

    //index = index where user input found in namefile 

    while ($point = current($namefile)){

        if($point == $search){

            ?>

            <div class="card">

                <img src="images/img.png">

                <h2 class="cardname"> <?php echo $namefile[key($namefile)]; ?></h2><br>

                <h2 class="cardnumber"><?php echo $cardnumberfile[key($namefile)]; ?> </h2><br>

                <h2 class="expirydate"> <?php echo $expirydatefile[key($namefile)]; ?> </h2>

            </div>

            <?php ;}

         else{

            echo "No match\n";

        } next($namefile);}

        ?>

</body>

</html>

My Answer:
This code looks mostly correct, but there are a few things that need to be adjusted.

1. The condition in the if statement should be checking if the user input matches the current element in the array, not the key. So it should be `$point` instead of `$namefile[key($namefile)]`.

2. The `next($namefile)` function should be outside of the if-else statement, so that it moves to the next element in the array regardless of whether there is a match or not.

3. You should also add a check to see if the form has been submitted before trying to access `$_POST["name"]`.

Here is the updated code:

php







    name: 



    


    






if(isset($_POST["submit"])) {

    //convert files to arrays

    $file1 = 'name.txt';

    $file2 = 'cardnumber.txt';

    $file3 = 'expirydate.txt';

    $namefile       = file($file1);

    $cardnumberfile = file($file2);

    $expirydatefile = file($file3);



    //put user input to variable

    $search = $_POST["name"];



    //display element with the same index in array namefile, cardnumberfile, and expirydatefile

    //index = index where user input found in namefile 

    while ($point = current($namefile)){

        if(trim($point) == $search){

            ?>

            

                

                 



                 



                  


            


            
        } 

        next($namefile);

    }

}

?>

This code should now correctly check if the user input matches any line in the `name.txt` file and display the corresponding information from the other files.

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John Davidson

html - PHP - Check if user input matches value in file that has been converted to array

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