John Davidson

Message:

I need to find an ID of an array that does not exist in the second array then know the ID. So for example eventid would be the same as id, I need to know if id does not exist in the second array but it does exist in the first array.

so 10001 = 10001, 10002 = 10002, 10003 = 10003, 10004 would be in the first array but not the second. How do I get the result of 1004 not being in the second array.

foreach($json as $eventinsert){   



$eventid = $eventinsert['objectId'];



$event = new Google_Service_Calendar_Event(array(

  'Id' => $eventinsert['objectId'],

  'summary' => $eventinsert['name'],

  'description' => $eventinsert['name'],

  'start' => array(

    'dateTime' => $eventinsert['dateStart']

  ),`enter code here`

  'end' => array(

    'dateTime' => $eventinsert['dateEnd']

  )

));

foreach ($events as $event) {

    $start = $event->start->dateTime;

    $id = $event->id;

    if (empty($start)) {

        $start = $event->start->date;



    }

   //     printf("%s (%s)\n", $event->getSummary(), $start);

   //     printf("%s (%s)\n", $event->getSummary(), $id);

    }

---

My Answer:
You can achieve this by using the array_diff() function in PHP. Here's an example of how you can find the IDs that exist in the first array but not in the second array:

php
$firstArray = array(10001, 10002, 10003, 10004);
$secondArray = array(10001, 10002, 10003);

$missingIds = array_diff($firstArray, $secondArray);

foreach($missingIds as $id){
echo $id . " is in the first array but not in the second array.";
}


In this example, the $missingIds array will contain the IDs that exist in the $firstArray but not in the $secondArray. You can then loop through the $missingIds array to get the IDs that are missing in the second array.