John Davidson

Message:

I'm trying to find & replace my values from inside string after getting values from inside loop.
When I replace my string from inside loop then(that method isn't suitable)as it replaces one by one until loop ends and I get a lot of strings with single replacements at each.
I'm trying to replace the whole string with loop values outside only once.
Here's my code.

$str = "wi are checking it";   

$langs = array ('w', 'c', 'i');

foreach ($langs as $lang) {

    $search = $lang;  

    $url[] = "<span style='color:red;'>".$search."</span>";

    $qw[] = $search;

}

$op = implode("", $url);

$er = implode("", $qw);

echo $op."<br>";

echo $er."<br>";

$new = str_replace($er, $op, $str);

echo $new;

It's output:

Expected Output:

[

---

My Answer:
a way to loop through an array in PHP and replace a specific value in a string only once. Here's an example of how you can achieve this:

php
$array = ['apple', 'banana', 'cherry'];
$string = 'I like to eat fruits like {fruit1}, {fruit2}, and {fruit3}';

foreach ($array as $key => $value) {
$placeholder = '{fruit' . ($key + 1) . '}';
$string = preg_replace('/' . preg_quote($placeholder, '/') . '/', $value, $string, 1);
}

echo $string;


In this code snippet, we have an array of fruits and a string with placeholders for each fruit. We loop through the array and replace each placeholder in the string with the corresponding fruit value. The `preg_replace` function is used with a limit of 1 to ensure that each placeholder is replaced only once.

After running this code, the output will be:

I like to eat fruits like apple, banana, and cherry


This way, you can dynamically replace values in a string based on an array in PHP.