John Davidson

Message:

I am trying to calculate the difference in days between the due date of an order and today's date.

I have the following code:

function dateDiffInDays($date1, $date2) {

   $diff = strtotime($date2) - strtotime($date1);

   $result = abs(round($diff / 86400));

   return $result;

}

When I call the function, $date1 is today and $date2 is the due date.

This works well, however if an order is overdue, that's to say $date2 is before $date1, the function doesn't return a negative number - meaning that the order looks as if it is not overdue.

I have attempted to use an if statement within the function, to multiply the $result by -1 $date1 is greater than $date2, but this returns strange results and feels a bit hacky.

I am therefore looking for help in changing this function so that it returns negative values, if $date1 is before $date2

---

My Answer:
function dateDiffInDays($date1, $date2) {
$diff = strtotime($date2) - strtotime($date1);
$result = round($diff / 86400);

if ($date1 > $date2) {
$result *= -1;
}

return $result;
}

This updated function should now return negative values if $date1 is before $date2, indicating that the order is overdue.